1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ratling [72]
3 years ago
7

Based on the sample of n = 25 healthy-weight students, can you conclude that healthy-weight students eat significantly fewer fat

ty, sugary snacks than the overall population? Use a one-tailed test with LaTeX: \alphaα. = .05

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

z = -1.645

Step-by-step explanation:

b) n =25, M = 4.01 , \mu = 4.22 , \sigma = 0.60 , \alpha= 0.05

The hypothesis are given by,

H0 : \mu\geq 4.22 v/s H1 : \mu < 4.22

The test statistic is given by,

Check attachment for the formula that should br here.

z = \frac{4.01- 4.22 }{0.60 /\sqrt{25}}

= -1.75

The critical value of z = -1.645

The calculated value z > The critical value of z

Hence we reject null hypothesis.

The healthy-weight students eat significantly fewer fatty, sugary snacks than the overall population.

Nat2105 [25]3 years ago
3 0

Answer:

Step-by-step explanation:

Null hypothesis, H₀ : μ ≥ 4.22

Alternative hypothesis, H₁ : μ < 4.22

Level of significance, ∝ = 0.05

Test statistic value Z = M₂ - μ / (δ/ √n)

                                   = 4.01 - 4.22 / 0.60 / √25

                                    = -1.75

P- value

P-value = P(Z < -1.75)

= P( Z ≤ -1.75)

= (=NORMSDIST(1.75))             (Use Ms Excel Function)

= 0.04005916

=0.0401

Decision: Reject  H₀ because the P-value is less than the 0.05 level of significance.

Conclusion, there is sufficient evidence that the number of snacks eaten by healthy-weight students is significantly less than the number for the general population at the 0.05 level of significance.

You might be interested in
On Mother’s Day,Mr.Davis took Mrs.Davis and their daughter,Sue,to a restaurant for dinner.All three ordered the Mother’s Day Spe
meriva

Answer:

$52.08

Step-by-step explanation:

Mr. Davis got the Mother's Day Special regularly priced, which is $24.80. For Mrs. Davis, 40% off of $24.80 is $14.88. For Sue, half of $24.80 is $12.40. Once you add them add up, you get $52.08.

4 0
3 years ago
Explain how the model represents 5/ 1third
Ilia_Sergeevich [38]

Here is ur perfect answer

3 0
2 years ago
Minerva buys used bicycles, repairs them, and sells them for a profit. She bought a bicycle for $10, repaired it, and sold it fo
STatiana [176]

it is an increase of 400%

3 0
3 years ago
Simplify 2 (n+1) + n² + 4 (n-3)
Gala2k [10]
2 (n+1) + n² + 4 (n-3) 
= 2n + 2 +  n² + 4n - 12 ...expand by using distributive property
=  n² + 6n - 10 ...combine like terms

hope it helps
4 0
3 years ago
Read 2 more answers
Your class earned $120.00 Saturday afternoon by washing cars to raise money for the class trip. This is 1/4 of the money needed
Ilya [14]

Answer:

$360.00

(I hope this was helpful)

5 0
2 years ago
Other questions:
  • Calculate straight time for 30 hours worked at $10.15 per hour
    5·2 answers
  • What is 50 divided by 2.5 divided by 0.04
    12·1 answer
  • Half a number x minus 5 is 11
    15·1 answer
  • U help factoring Trinomial plz
    11·1 answer
  • Find the eleventh term of the arithmetic sequence whose sixth term is 41, and whose fourteenth term is 97?
    7·1 answer
  • Triple 3, then add s to the result
    9·1 answer
  • The mean value of land and buildings per acre from a sample of farms is ​$1500​, with a standard deviation of ​$200. the data se
    6·1 answer
  • M∠6 is (2x – 5)° and m∠8 is (x + 5)°.
    7·2 answers
  • Al calcular “x” en la siguiente igualdad arcocos √3 / 2 = arcsenx el resultado es: (justifique su respuesta)
    6·1 answer
  • MATH<br> can somebody answer these questions for me??
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!