Answer:
Step-by-step explanation:
The complete question tells us that;
A dataset from a government survey contains variables for 87 adults age from 18 to 85. The variables include iron level ( µ g/dL), cholesterol level (mg/dL), and systolic blood pressure (mmHg). The researchers built a multiple regression to predict the mean iron level based on 2 variables, cholesterol level and systolic blood pressure.A partial regression ANOVA table is provided. Complete the ANOVA table aning. Use a significance level of a 0.05. Regression ANOVA Table Source df SSMSF Statistic p-value regression104535226.5 error 84 53813 640.6 Give the degrees of freedom as a whole number, the value of F to at least two decimals, the the p-value to at least three decimals. Then form the conclusion based on your results.
NOTE: the attached minilab worksheet calculates this problem.
below is the attached image.
Answer: their speeds are 3.5mph and 4 mph
Step-by-step explanation:
Since both friends live 3 miles apart along the same road, by the time they meet, they would have covered 3 miles.
Let x represent the speed of the slower friend.
If differ by half mile per hour, it means that the speed of the faster friend is (x + 0.5) mph
They meet after 24 minutes(24/60 = 0.4 hours)
Distance = speed × time
Distance covered by the slower friend in 0.4 hours is
x × 0.4 = 0.4x
Distance covered by the faster friend in 0.4 hours is
0.4(x + 0.5) = 0.4x + 0.2
Since the total distance is 3 miles, then
0.4x + 0.4x + 0.2 = 3
0.8x = 3 - 0.2 = 2.8
x = 2.8/0.8
x = 3.5 mph
The speed of the faster friend is
3.5 + 0.5 = 4 mph
Answer:
5.3 units
Step-by-step explanation:
the height of point p from line MN is 5.3 units
plz give me brainliest
60% = 372
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Find 1 %
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60% = 372
1% = 372 ÷ 60
1% = 6.2
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Find 100%
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1% = 6.2
100% = 6.2 x 100
100% = 620
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Answer: There are 620 students in the school.
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Answer:histogram 4
Is this for stats? each number is going by 5 and looking at the numbers you can easily eliminate 2 and 3 as there is nothing in the area of 50-60 that only leaves 1 and 4 look at the numbers and how they add up in the frequency from 70-75 there are two numbers that meet the criteria. Histogram 1 only shows one number for that section so i assume that it should be number 4.
