Answer:
The correct answer is 160.
Explanation:
Based on the given question, the total number of fruit flies is 1000, of which red eye flies are 640. Thus, the number of sepia eye flies will be 1000-640 = 360.
On the basis of the Hardy-Weinberg equation, p+q = 1, in which p is the rate of recurrence of one allele, that is, dominant and q is the rate of recurrence of the other allele, that is, recessive.
q^2 for the population is 360/1000 = 0.36, q = 0.6.
Therefore, p = 1-q = 1-0.6 = 0.4.
The frequency of homozygous dominant allele is denoted by p^2 = 0.16.
Hence, the number of homozygous dominant for red eye color would be 16% of 1000 which will be equal to 160.
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C. F1 generation is all Yy (let Y be yellow and y be green). Y is dominant to y. The F2 could be YY, Yy, Yy, or yy. 3:1