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ratelena [41]
3 years ago
7

the scale of a scientific drawing is 1cm = 2 in., If the actual length of an object in the drawing was 4.5 inches, how long woul

d it be in the drawing?
Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
2.25cm because the drawing is 1/2 the size of the object
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marissa [1.9K]
The answer is 3 :) hope this is right
3 0
3 years ago
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Solve.
ArbitrLikvidat [17]

The solution for the system equations is (2 , 0 , -2).

<h3>System of Equations</h3>

A system of equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point of the intersection.

You can solve a system of equations by the adding or substitution methods. In the addition method, you eliminate a variable, on the other hand, in the substitution method you replace a variable for the other. To solve this question, you will apply the addition method.

The question gives three equations:

(1) 4x−2y+z=6

(2) −2x+y=−4

(3) 3y−2z=4

You should isolate the variable x in equation (2), then you will have

x=-\frac{-4-y}{2}. After that, you should use this variable in equation (1), see below

Equation 1 (4x−2y+z=6)

4(-\frac{-4-y}{2})-2y+z=6\\ \\ 8+2y-2y+z=6\\ \\ 8+z=6\\ \\ z=6-8\\ \\ z=-2

If z=-2, from equation (3), you find y, see below.

3y-2z=4

3y-2*(-2)=4

3y+4=4

3y=4-4

3y=0

y=0

If y=0, from equation (2), you find x, see below.

−2x+y=−4

-2x+0=-4

-2x=-4

x=2

Read more about solving systems equations here:

brainly.com/question/12691830

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3 0
1 year ago
Bert has 10 books and he wants to give 2 of these books to his sister. How many different gifts are possible?
tia_tia [17]

Answer:

10 difderent gifts are possible

7 0
2 years ago
a car was valued at $41,000 in the year 2009 by 2013 the car value has depreciated to 19,000 if the car value continues to by th
lubasha [3.4K]

Answer:

$6,376.92

Step-by-step explanation:

-Let d be the rate of depreciation per year.

-Therefore, the value after n years can be expressed as:

A=P(1-d)^n\\\\A=Value \ after \ n  \ years\\P=Initial \ Value\\d=Rate \ of \ depreciation\\n=Time \ in \ years

#We substitute for the years 2009-2013 to solve for d:

A=P(1-d)^n\\\\19000=41000(1-d)^4\\\\0.475=(1-d)^4\\\\d=1-0.475^{0.25}\\\\d=0.1698

#We then use the calculated depreciation rate above to solve for A after 10 yrs:

A=P(1-d)^n\\\\=41000(1-0.1698)^{10}\\\\=\$6,376.92

Hence, the value of the car after 10 yrs is $6,376.92

3 0
3 years ago
I need helppppppppppppppppppppppppppppppppppppppp
Archy [21]

Answer:

C. 6.2 inches

Step-by-step explanation:

There are many ways to do this but I like to cross the miles out by putting it on the denominator

927 miles * 1 inch/150 miles = 6.18

Rounded is 6.2

3 0
3 years ago
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