Answer:
f=14 or f=34
Step-by-step explanation:
(x+d)(x+e) =x^2 +fx+33, d, e, f>0
x^2 +xe+dx+de=x^2+fx+33
x^2+(e+d)x+de=x^2 +fx+33 that
e+d=f and d*e=33, d=33/e
e+33/e=f
33=1*33 or 33=3*11
If e=1,d=33 then f=34
If e=3*,d=11, then f=14
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
Answer:
y=0.25x-6
Step-by-step explanation:
The point is not a solution to the equation of the line.
Hope this helps!