Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given
recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
Distribute.
(a + 8)(a -3)
FOIL:
First, Outside, Inside, and Last
a * a = a^2
a * 3 = 3a
8 * a = 8a
8 * -3 = - 24
a^2 + 11a - 24
Distributed Expression: a^2 + 11a - 24
Answer:
C
Step-by-step explanation:
g(x) = 4x²
g(x) is steeper than f(x) and the ordered pair (1, 4) fits in option C:
g(1) = 4(1)² = 4
Answer:
2:55 P.M.
Step-by-step explanation:
First, add the amount of time Jim played outside; 45+55=100
100 minutes is equal to 1 hour 40 minutes.
If he left the playground at 4:35 P.M., then you have to subtract in order to find out when he arrived there.
Subtract 1 hour 40 minutes from 4:35 P.M. to then get 2:55 P.M.
To confirm your answer, you can add back the 1 hour and 40 minutes to 2:55 P.M. and you'll get 4:35 P.M.; back with what you started with.
Hope this helped !!!
