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Semenov [28]
2 years ago
8

I am soooo confuseddd what the heckkk Ok so Im doing something called 'Graphing Systems of Linear Equations' , well you might sa

y its easy but I never understood something in the last lesson to begin with so this is like so freaking frustrating. Im looking at examples but it doesnt make sensssse help Ok so look at the screenshot. Why is one point on the line -4
and for the person who deleted my question lasttime, please stop. Try to see it from my perspective, Im desperate for homework help cuz obviously I don't want to fail and want to understand the lesson and get my homework done, checking to see if someone answered my question every 5 mins, and instead I see someone deleted it.

Please help???

-fellow student

Mathematics
1 answer:
horsena [70]2 years ago
4 0
Okay, so the equation for the y-intercept is y=mx+b, this will be your base for graphing anything.

For y = x + 3 it's basically y = 1x + 3. Use b as the y-intercept, or 3, and plot it as (x,y), (0,3). Then use m as the slope, or 1. 1 means positive one so the point goes (0,3), (1, 4), (2, 5).

For y = -3x - 1 it's the same thing but different numbers. Use b, the y-intercept, and plot it. -1 is b, so plot (0,-1). Then use the slope to go up or down the direction you need to go, or m. m is -3, so for every +1 in x, the y will decrease by 3. (0,-1), (0,-4), (0,-7).

I hope this helped in some way or increased your understanding!
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Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values below. find each missing value and then
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Given the function :

f(x)=\sqrt[]{x+2}+1

We need to find each missing value

Given x = -3 , -2 , -1 , 2 , 7

So, substitute with each value of x to find the corresponding value of f(x)

x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1

So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)

\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\  \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\  \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\  \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}

the graph of the function and the points will be as shown in the following image :

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What is the complement of an angle that measures 43 deegress ?
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Identify the reflection of the figure with vertices E(8,4), F(-16,-8), and G(24,-16) across the y-axis.
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Answer:

\boxed{\text{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}

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When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

E (8,4) ⟶ E' (-8,4)

F (-16,-8) ⟶ F' (16,-8)

G (24,-16) ⟶ G' (-24,-16)

\text{The reflected figure has coordinates } \boxed{\textbf{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}

The figure EFG and its reflection E'F'G' are shown in the diagram below.

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