I am soooo confuseddd what the heckkk Ok so Im doing something called 'Graphing Systems of Linear Equations' , well you might sa
y its easy but I never understood something in the last lesson to begin with so this is like so freaking frustrating. Im looking at examples but it doesnt make sensssse help Ok so look at the screenshot. Why is one point on the line -4 and for the person who deleted my question lasttime, please stop. Try to see it from my perspective, Im desperate for homework help cuz obviously I don't want to fail and want to understand the lesson and get my homework done, checking to see if someone answered my question every 5 mins, and instead I see someone deleted it.
Okay, so the equation for the y-intercept is y=mx+b, this will be your base for graphing anything.
For y = x + 3 it's basically y = 1x + 3. Use b as the y-intercept, or 3, and plot it as (x,y), (0,3). Then use m as the slope, or 1. 1 means positive one so the point goes (0,3), (1, 4), (2, 5).
For y = -3x - 1 it's the same thing but different numbers. Use b, the y-intercept, and plot it. -1 is b, so plot (0,-1). Then use the slope to go up or down the direction you need to go, or m. m is -3, so for every +1 in x, the y will decrease by 3. (0,-1), (0,-4), (0,-7).
I hope this helped in some way or increased your understanding!
Step-by-step explanation: well first think of what number can divide into 40 and 35 and come out as 5. So for example 35 divided 7 equals 5 and 40 divided 8 = 5 so the missing number is either 8 or 7
number of favourable outcomes/total number of possible outcomes
Looking at the given scenario, the number os students that earned a grade of A is 5. Since we are concerned with these students, then, the number of favourable outcomes is 5.
The total number of students for all grades is 35. This means that the total number of possible outcomes is 35
Thus, the probability that a student earns a grade of A is