The answer is -76.1 meters.
The submarine elevation before rising is -203 meters (it is negative because it is under the sea level which has 0 elevation): d₁ = -203 m
After the first rising, it moved 64.5 m: l₁ = 4.3 · 15 = 64.5 m
After the second rising, it moved 62.4 m: l₂ = 5.2 · 12 = 62.4 m
So, to calculate <span>the elevation of the submarine after rising (d</span>₂), we will add (because it is not going deeper, it rises toward the elevation of 0) two movements to the elevation before rising:
d₂ = d₁ - (l₁ + l₂) = -203 + (64.5 + 62.4) = -203 + 126.9 = -203 + 126.9 = -76.1.
we have that
A+B=B+A -------> is the same
so
B+A= (1-5) (-3+3) (4-5) (-5-2)
(2-4) (5-2) (-4+4) (4-5)
<h2>B+A= -4 0 -1 -7</h2><h2> -2 3 0 -1</h2>
Answer:
(-29)/30
Step-by-step explanation:
Simplify the following:
-(2 + 4/5) + (1 + 5/6)
Put 2 + 4/5 over the common denominator 5. 2 + 4/5 = (5×2)/5 + 4/5:
-(5×2)/5 + 4/5 + 1 + 5/6
5×2 = 10:
-(10/5 + 4/5) + 1 + 5/6
10/5 + 4/5 = (10 + 4)/5:
-(10 + 4)/5 + 1 + 5/6
10 + 4 = 14:
-14/5 + 1 + 5/6
Put (-14)/5 + 1 + 5/6 over the common denominator 30. (-14)/5 + 1 + 5/6 = (6 (-14))/30 + 30/30 + (5×5)/30:
(6 (-14))/30 + 30/30 + (5×5)/30
6 (-14) = -84:
(-84)/30 + 30/30 + (5×5)/30
5×5 = 25:
(-84)/30 + 30/30 + 25/30
-84/30 + 30/30 + 25/30 = (-84 + 30 + 25)/30:
(-84 + 30 + 25)/30
| 3 | 0
+ | 2 | 5
| 5 | 5:
(55 - 84)/30
55 - 84 = -(84 - 55):
(-(84 - 55))/30
| 7 | 14
| 8 | 4
- | 5 | 5
| 2 | 9:
Answer: (-29)/30
Answer: 55 miles per hour
Step-by-step explanation:
Here is the complete question:
Seth's family plans to drive 220 miles to their vacation spot. They would like to complete the drive in 4 hours.
Find the average speed in miles per hour needed to make the trip in the desired.
From the question, Seth's family plans to drive 220 miles to their vacation spot and they would like to complete the drive in 4 hours.
Average speed is calculated as distance travelled divided by the time taken. This will be:
Speed = Distance/Time
Average speed = 220/4
Average speed = 55 miles per hour
It should be B. right angle and C. complementary angles
