There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
Your answer would be 95 calories per apple
Answer:
3.2t - 2.4
Step-by-step explanation:
Given
- 3.6 - 1.9t + 1.2 + 5.1t ← collect like terms
= (- 1.9t + 5.1t) + (- 3.6 + 1.2)
= 3.2t + (- 2.4)
= 3.2t - 2.4
Answer:
$600
Step-by-step explanation:
Let "x" represent their total budget for the film.
Amount spent on costumes = $330
Percent spent on costumes = 55%
Therefore:
55% of x = $330
55/100 × x = 330
55x/100 = 330
Cross multiply
55x = 100 × 330
55x = 33,000
Divide both sides by 55
x = 33,000/55
x = 600
Total budget = x = $600
Answer:
2x * (9 + 5x^2)
Step-by-step explanation:
