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nirvana33 [79]
4 years ago
12

Please help me with this math question

Mathematics
1 answer:
just olya [345]4 years ago
8 0

Answer:

The yellow rectangle was reflected over the x -axis. is correct


Step-by-step explanation:

The correct answerrs are : (both in the positive side of the y axis or the negative side of the x axis , or above the x axis or to the left of the y axis.


the statement: The yellow rectangle was traslated down 3 unitis (does not say that is regarding the x axis) there fore is not completely true

the yellow rectangle was translated right 3 units (is incorrect because it has been traslated left 3 units)

the first stamente dos not specify wich side of the blue rectangle was reflected (left or right) over the positive side of the y axis

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3x=42
x=42/3
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in a certain population, 11% of people are left-handed. Suppose that you plan to randomly select 100 people and ask each person
Assoli18 [71]

Answer:

c. A and C

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=100, p=0.11)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=100*0.11=11 > 10 \geq 10

n(1-p)=100*(1-0.11)=99 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=100*0.11=11

\sigma=\sqrt{np(1-p)}=\sqrt{100*0.11(1-0.11)}=3.129

Part A

We want this probability:

P(X \geq 12) = 1-P(X

The z score is defined as

Z=\frac{x-\mu}{\sigma}.

P(X \geq 12) = 1-P(X

Part B

P(X>12) = 1-P(X\leq 12) = 1-P(Z< \frac{12-11}{3.129})=1-0.625=0.375[/tex]

Part C

P(10\leq X \leq 14) = P(X

The z score is defined as

Z=\frac{x-\mu}{\sigma}.

P(10 \leq X \leq 14) =P(Z< \frac{14-11}{3.129}) -P(Z< \frac{10-11}{3.129})=P(Z

So then the best option is : c. A and C

8 0
4 years ago
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