Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD =
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
=
=
= 0.6
The dimensions are 15x35 meters
Six point eight four.
(Note, you don't say, "Six point eighty-four" As it doesn't sound correct.
Cheers.
2 to the left is 3 your very welcome hope this helps
Step-by-step explanation:
1.(2,3)
2.No
3.1st quadrant
4.5
5.Yes
6.Quadrant-4
7.(2,-3)