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Nookie1986 [14]
3 years ago
11

A pole that is 3.3 m tall casts a shadow that is 1.29 m long. At the same time, a nearby tower casts a shadow that is 36.75 m lo

ng. How tall is the tower?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0
Check the picture below.

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Pls help<br> will mark brainliest
yanalaym [24]

Answer:

1.93433

Step-by-step explanation:

Since all triangles have an interior angle sum of 180, the second angle is 45. this also means that x and y are equal. Using the pythagorean theorem, we can produce the equation 2\sqrt{14} = 2x^2. dividing both sides by two we get x^2= \sqrt{14}. when we take the square root of root 14 we get 1.934335

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The elevator will be on the 76th floor in 60 seconds.
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A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Katyanochek1 [597]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

                                                 =( \pi \times 2^2\times h)\ m^3

\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

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3 years ago
Evaluate the expression. (343)^-1/3​
Otrada [13]

Answer:

THE ANSWER IS 1/7

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2 years ago
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