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sergejj [24]
3 years ago
6

What is the vertex of y = (x + 5)^2 - 6

Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0
I hope this helps you

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What’s the slope of the parallel line that passes through (-19, 14) and (19, 11).
laiz [17]

Answer:

19,12

Step-by-step explanation:

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3 years ago
The attendance at a seminar in 1 year was 500. in year 2, the attendance changed by 100. what was the percent change in the atte
Masja [62]

Answer:

C

Step-by-step explanation:

100/500=0.2

0.2=20%

3 0
3 years ago
Read 2 more answers
Adidea Corp. estimates that $5,670 of its accounts receivables are uncollectible. How will the company record the transaction?
sergiy2304 [10]

Answer:

The transaction will be recorded by the company as :

DR : Non-collectibles $5670  

CR : Accounts receivable $5670

Step-by-step explanation:

Amount of money estimated = $5670

The amount which is non-collectible is recorded as a DEBIT transaction by the company because the amount in the non-collectible account can't be received by the company.

But, the amount in the receivables is the amount which is available for receiving and can be received by the company. So, receivable transaction is marked as CREDIT by the company.

Thus, the transaction will be recorded by the company as :

DR : Non-collectibles $5670  

CR : Accounts receivable $5670

4 0
3 years ago
A. (x, y) → (x, y + 4)
Harrizon [31]
X444444xxx-xxxx444468
3 0
3 years ago
PLEASE HELP ASAP!!!!
Setler [38]

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.

To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.

Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.

Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.

Therefore:

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 8}  \\ f(4) = 3 \end{cases}}

The nth root of a can contain negative number only if n is an odd number.

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 2 \times -  2 \times   - 2}  \\ f(4) = 3 \end{cases}} \\  \large{  \begin{cases} f( - 8 ) =  - 2\\ f(4) = 3 \end{cases}}

Answer

  • f(-8) = -2
  • f(4) = 3
6 0
2 years ago
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