Answer:
A: yes because the sample is fairly small and is collected in a convenient manner
We'll use the formula for the classical probability as follows.
P(A) = Number of outcomes favorable for A / Total number of possible outcomes
In this case, two socks are randomly drawn from a set of 6+10 = 16 socks. So the total number of possible outcomes = 16C2 = 120.
The two stocks match each other if they are both blue or grey. So the number of favorable outcomes is 6C2 + 10C2 = 15 + 45 = 60.
Hence the probability that the two stocks match is
![\frac{60}{120}=0.5](https://tex.z-dn.net/?f=%20%5Cfrac%7B60%7D%7B120%7D%3D0.5%20)
.
Answer: The same number of tickets was sold on the fourth day and tenth day.
Step-by-step explanation:
Given, T(d) is a function that relates the number of tickets sold for a movie to the number of days since the movie was released.
The average rate of change in a function with respect to the independent variable gives the value of change in a particular period.
If average rate of change in T(d) for the interval d = 4 and d = 10 is is 0 , that means nothing has been changed in the number of tickets sold on 4th day and 10th day after the film release.
Hence, the correct statement is "The same number of tickets was sold on the fourth day and tenth day."
Answer:
<h2>0.75(3/4) part of the room</h2>
Step-by-step explanation:
Step one:
given data
we can express the given data mathematically as
John can paint 0.5room in 2/3 hours
let the part of the room he can paint in an hour be x
so
if he takes 2/3 hours to paint 0.5 room
then he will take 1 hour to paint x
cross multiply we have
x= 0.5/2/3
x=0.5*3/2
x= 1.5/2
x=0.75 part of the room
75/100= 15/20=3/4 part