All categories

2 years ago

If John can paint half of a room in two-thirds of an hour, what part of the room can he paint in a full hour?

Mathematics

1 answer:

Firlakuza [10]2 years ago

5 0

Answer:

Step-by-step explanation:

Step one:

given data

we can express the given data mathematically as

John can paint 0.5room in 2/3 hours

let the part of the room he can paint in an hour be x

if he takes 2/3 hours to paint 0.5 room

then he will take 1 hour to paint x

cross multiply we have

x= 0.5/2/3

x=0.5*3/2

x= 1.5/2

x=0.75 part of the room

75/100= 15/20=3/4 part

You might be interested in

What is the slope of the line?

xeze [42]

Answer:

1/3

Step-by-step explanation:

Slope is rise over run.

Pick a point and count how many steps up and how many steps to the right you need to make to get to the next point. That's how you find slope.

3 0

1 year ago

Find the slope(11,-18) (-1,-7)

mestny [16]

Answer:

-11/12

Step-by-step explanation:

→ Find change in y

-7 --18 = 11

→ Find change in x

-1 - 11 = -12

→ Divide each other

-11/12

8 0

2 years ago

I'll mark as brainliest if you get the answer correct with Explanation.

mrs_skeptik [129]

Answer:

25, 90, and 65

Step-by-step explanation:

so the measures have to add up to 180, because it's a triangle, and we know 25 and 90 ( the box corner thing means that angle is 90) so we add 25 and 90 to get 115, and then we subtract 115 from 180, which gets us 65.

6 0

2 years ago

A dictionary contains the following 10 words: a, the, your, blue, red, purple, card, token, hat, shirt.

Serhud [2]

Answer:

0.1

Step-by-step explanation:

because the probability is 1 out of 10 so if you divide 1/10 it is equal to 0.1

8 0

2 years ago

Read 2 more answers

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

7 0

2 years ago