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Kipish [7]
3 years ago
6

In your top dresser drawer are 6 blue socks and 10 grey socks, unpaired and mixed up. one dark morning you pull two socks from t

he drawer (without replacement, of course!). what is the probability that the two socks match?
Mathematics
1 answer:
beks73 [17]3 years ago
4 0
We'll use the formula for the classical probability as follows.

P(A) = Number of outcomes favorable for A / Total number of possible outcomes

In this case, two socks are randomly drawn from a set of 6+10 = 16 socks. So the total number of possible outcomes = 16C2 = 120.

The two stocks match each other if they are both blue or grey. So the number of favorable outcomes is 6C2 + 10C2 = 15 + 45 = 60.

Hence the probability that the two stocks match is \frac{60}{120}=0.5.
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Hello there!
First, divide 144 with 16 = 144 ÷ 16 = 9
Now, just multiply 9 with 10 = 9 x 10 = 90
Your pay for 10 hours was $90
I hope I helped!
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For an acute angle θ, the equation sin (θ) = cos (7°)is true. What is the value of θ?
8_murik_8 [283]

Answer:

  θ = 83°

Step-by-step explanation:

For acute angles, the sine of an angle is the cosine of its complement, and vice versa.

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5 0
2 years ago
A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec
Paraphin [41]

Answer:

A. The solutions are x=3i,\:x=-3i.

B. The factored form of the quadratic expression x^2+9=(x-3i)(x+3i)

Step-by-step explanation:

A. To find the solutions to the quadratic equation x^2+9=0 you must:

\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}

x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i

The solutions are:

x=3i,\:x=-3i

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor x^2+9:

First, multiply the constant in the polynomial by i^2 where i^2 is equal to -1.

x^2+9i^2

Since both terms are perfect squares, factor using the difference of squares formula

a^2-i^2=(a+i)(a-i)

x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)

5 0
3 years ago
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