12 = 2*2*3
10 = 5*2
LCM = 5*3*2*2
= 15*4=60
the least common multiple is 60
If the coefficient matrix has a pivot in each column, it means that it is shaped like this:
![A=\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7Da_%7B1%2C1%7D%26a_%7B1%2C2%7D%26a_%7B1%2C3%7D%26a_%7B1%2C4%7D%5C%5C0%26a_%7B2%2C2%7D%26a_%7B2%2C3%7D%26a_%7B2%2C4%7D%5C%5C0%260%26a_%7B3%2C3%7D%26a_%7B3%2C4%7D%5C%5C0%260%260%26a_%7B4%2C4%7D%5Cend%7Barray%7D%5Cright%5D)
So, the correspondant system

will look like this:
![\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]\cdot \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] = \left[\begin{array}{c}b_1\\b_2\\b_3\\b_4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7Da_%7B1%2C1%7D%26a_%7B1%2C2%7D%26a_%7B1%2C3%7D%26a_%7B1%2C4%7D%5C%5C0%26a_%7B2%2C2%7D%26a_%7B2%2C3%7D%26a_%7B2%2C4%7D%5C%5C0%260%26a_%7B3%2C3%7D%26a_%7B3%2C4%7D%5C%5C0%260%260%26a_%7B4%2C4%7D%5Cend%7Barray%7D%5Cright%5D%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%5C%5Cx_2%5C%5Cx_3%5C%5Cx_4%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Db_1%5C%5Cb_2%5C%5Cb_3%5C%5Cb_4%5Cend%7Barray%7D%5Cright%5D)
This turn into the following system of equations:

The last equation is solvable for
: we easily have

Once the value for
is known, we can solve the third equation for
:

(recall that
is now known)
The pattern should be clear: you can use the last equation to solve for
. Once it is known, the third equation involves the only variable
. Once
A. It's a composite function, so basically, wherever you see a p, replace it with 5t, because we are given that information. So, your answer is:
B. Let's use the function we created, and just plug in 2 for t:
![A[p(2)] = 10(2) \pi](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%20%3D%2010%282%29%20%5Cpi%20)
![A[p(2)] = 62.83](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%3D%2062.83)
So, your answer is
(approximately)
62.83 units².
Answer:
y=4x
Step-by-step explanation:
The line goes through the points (0, 0) and (2, 8).
You can plug these in to the slope formula, and the slope is 4
Since the line intersects the y-axis at 0, the y-intersect is 0.
Using these two pieces of information, you now know that the equation is
y=4x+0, or y=4x.
Hope this helps!
Answer:
Perimeter = 8x
Step-by-step explanation:
If I can see correctly, the area of the squares are x². Area is just s², so we can find one side by finding the square root of x², which is x. Now that we know that x is one side, we can count the amount of sides and multiply that number by x.
There are 8 sides, so the answer is P = 8x