Question

Could somebody please answer these four questions with simple yet explanatory answers?

Answer 1

Pooja answered #1 and #2 correct, so I shall make my life easier by answering #3 and #4 :P

#3 tests the concept of surface area. The gift wrap will be covering only the surface of each side. Surface area is all of the outside. Volume is all of the stuff inside.

So the surface area of rectangular prism can be found by the formula:
SA = 2(LW + LH + WH)
SA = 2(9*7 + 7*4 + 9*4)
SA = 2(63 + 28 + 36)
SA = 2(127)
SA = 254 in²

#4 also needs you to find the surface area. 
So the surface area of a triangular prism can be found by this formula:
SA = bh + ($\sf s_1 + s_2 + s_3$)h
SA = (6.3*2) + (6.3 + 2.5 + 5.2)3
SA = 12.6 + (14*3)
SA = 12.6 + 42
SA = 54.6 cm²

Answer 2

1) Surface Area = 2(lw + lh + wh)
2(4*5+4*9+5*9) =202in^2
Surface Area=202in^2
Lateral Area= Perimeter of base * height
5+5=10  <--width+width
4+4=8 <---length + length 
10+8=18  <--total perimeter
18 * 9=162in^2  <--multiplied the height +perimeter of base  
Lateral Area=162in^2

2) Same concept as the previous one
 Surface Area = 2(lw + lh + wh)
2(4*2+4*5+5*2) =76in^2
Surface Area= 76in^2

Lateral Area
Lateral Area= Perimeter of base * height
4+4=8
2+2=4
8+4=12
12 x 5=60
Lateral Area= 60in^2