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trapecia [35]
3 years ago
8

A water park charges $5 for entry into the park and an additional $2 for each of the big water slides. Steven spent $17 on his v

isit to the water park. Which equation can be used to find the number of big water slides, x, that Steven went on?
5 + 2x = 17
5x + 2 = 17
5x + 2x = 17
5 + 2 = 17x
Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0
The answer would be a 
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Need help with homework
zubka84 [21]

Answer:

5. the other angle has to be 2x because of the other lines being equals so

2x+2x+x-15=180

5x-15=180

5x=195

x=19

6. the other two angle is ajacent to the other two so

3x+17+3x+17+x-9+x-9=360

8x+16=360

8x=344

x=43

7. this ones pretty simple

2x-4+3x+5+2x+11=180

7x+12=180

7x=168

x=24

8. this one to

x+x+4+3x-9=90

5x+5=90

5x=85

x=17

Hope This Helps!!!

5 0
2 years ago
The perimeter of a notebook is 44 inches the notebook is 10 inches wide how tall is it?
tatyana61 [14]
Answer=36inches tall

Explanation= 44+10= 54
90-54=36in
5 0
3 years ago
What slope is parallel to:<br> m = 4
andreyandreev [35.5K]

Answer:

m = 4

Step-by-step explanation:

Parallel means to have the same slope but different x- and y- intercepts

An example would be y = 4x + 6 and y = 4x - 2

8 0
3 years ago
PLEASE HELP SCHOOLS ALMOST OVER AND I NEED THIS
jekas [21]

Answer: A (10)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
3 years ago
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