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devlian [24]
3 years ago
10

12÷4+1312÷4+13 ? 2+22÷22+22÷2 a = b < c >

Mathematics
1 answer:
docker41 [41]3 years ago
5 0
C > because the first one equals 344 and the second one equals 14
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How long will it take to administer 1000 cc at a drop factor of 15 drop/ml and a drip rate of 50 drop/min
gayaneshka [121]
First, we are going to determine the number of drops that needs to be administered by dividing the total volume by the volume per drop. Since, 1 cc (cm³) is equal to 1 mL then, 1000 cc is equal to 1000 mL.

   n = (1000 mL)(15 drop/1 mL) = 15000 drops

Then, divide the number of drops by the number of drops per minute.

   N = (15000 drops)/ (50 drop/min) = 300 mins

Answer: 300 mins or 5 hours
5 0
3 years ago
How do I write the number 17,497,403 well i know how to do it inside standard but my equation says “Write the number Seventeen m
MrRa [10]

Step-by-step explanation:

Standard form is of course 17,497,403.

Expanded form is:

10,000,000 + 7,000,000 + 400,000 + 90,000 + 7,000 + 400 + 3

7 0
3 years ago
Are 5/6 and -4.713 on the same side or the opposite side of zero ?
Alchen [17]
They are on opposite sides of zero because one number is negative and one is positive
8 0
3 years ago
A Ferris wheel is 20 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position
pantera1 [17]

Answer:

233.48s  

3.84 min

Step-by-step explanation:

In order to solve this problem, we can start by drawing what the situation looks like. See attached picture.

We can model this situation by making use of a trigonometric function. Trigonometric functions have the following shape:

y=A cos(\omega t+\phi)+C

where:

A= amplitude =-20m because the model starts at the lowest point of the trajectory.

f= the function to use, in this case we'll use cos, since it starts at the lowest point of the trajectory.

t= time

\omega= angular speed.

in this case:

\omega=\frac{2\pi}{T}

where T is the period, in this case 6 min or

6min(\frac{60s}{1min})=360s

so:

\omega=\frac{2\pi}{360}

\omega = \frac{\pi}{160}

and

\phi= phase angle

C= vertical shift

in this case our vertical shift will be:

2m+20m=22m

in this case the phase angle is 0 because we are starting at the lowest point of the trajectory. So the equation for the ferris wheel will be:

y=-20 cos(\frac{\pi}{180}t)+22

Once we got this equation, we can figure out on what times the passenger will be higher than 13 m, so we build the following inequality:

-20 cos(\frac{\pi}{180}t)+22>13

so we can solve this inequality, we can start by turning it into an equation we can solve for t:

-20 cos(\frac{\pi}{180}t)+22=13

and solve it:

-20 cos(\frac{\pi}{180}t)=13-22

-20 cos(\frac{\pi}{180}t)=-9

cos(\frac{\pi}{180}t)=\frac{9}{20}

and we can take the inverse of cos to get:

\frac{\pi}{180}t=cos^{-1}(\frac{9}{20})

which yields two possible answers: (see attached picture)

so

\frac{\pi}{180}t=1.104 or \frac{\pi}{180}t=5.179

so we can solve the two equations. Let's start with the first one:

\frac{\pi}{180}t=1.104

t =1.104(\frac{180}{\pi})

t=63.25s

and the second one:

\frac{\pi}{180}t=5.179

t=5.179(\frac{180}{\pi})

t=296.73s

so now we can build our possible intervals we can use to test the inequality:

[0, 63.25]  for a test value of 1

[63.25,296.73] for a test value of 70

[296.73, 360] for a test value of 300

let's test the first interval:

[0, 63.25]  for a test value of 1

-20 cos(\frac{\pi}{180}(1))+22>13

2>13 this is false

let's now test the second interval:

[63.25,296.73] for a test value of 70

-20 cos(\frac{\pi}{180}(70))+22>13

15.16>13 this is true

and finally the third interval:

[296.73, 360] for a test value of 300

-20 cos(\frac{\pi}{180}(300))+22>13

12>13 this is false.

We only got one true outcome which belonged to the second interval:

[63.25,296.73]

so the total time spent above a height of 13m will be:

196.73-63.25=233.48s

which is the same as:

233.48(\frac{1min}{60s})=3.84 min

see attached picture for the graph of the situation. The shaded region represents the region where the passenger will be higher than 13 m.

3 0
3 years ago
For which equation is x=35 a solution​
SIZIF [17.4K]

Answer:

C- 105/35=3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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