Answer:
It will take 25.7 minutes when they are working together
Step-by-step explanation:
Here, we want to know how long it will take both pipe working together to drain the tank
Let the volume of water to be drained be xL
for the first one, rate is
x/45 L/minutes
for the second x/60 L/minutes
Joint rate will be
x/45 + x/60 = 4x + 3x/180 = 7x/180
Now go get the time involved here, we simply divide the volume by the rate
That would be;
x divided by 7x/180
= x * 180/7x
= 180/7 = 25.7 minutes
Step-by-step explanation:
If all of these are supposed to be a length in a different dimension (a 6d object), then just multiply all of them like you would do in 3d.
14*8*10*10*10*8 = 896000 cm^6
If this is supposed to be a 3d object and all the sides with equal length are just supposed to be going in the same direction, multiply one of each of the lengths.
14*8*10 = 1120 cm^3
Answer:
47
Step-by-step explanation:
You would divide 141 by 3 because there was three sweatshirts bought, so the answer from that would be the price of one.
141/3=47
Answer:
This college library would hold approximately ![6*10^{5}/tex] books.Step-by-step explanation:Having books on both sides, and each book being 25 centimeters (there is 100 cm in a meter, so 25 cm=0.25 m) deep, shelves must be around 50 cm (or 0.5 m) wide.If corridors must be 1,5 m wide, every two linear meters (perpendicular to corridors and shelves) of floor space there is 1.5 m of corridors and 0.5 m of shelves and that sequence repeats itself, i.e. there is 75% (1.5 of every 2 meters) of space occupied by corridors and 25% (0.5 of every 2 meters) occupied by shelves, that is:[tex]Floor space_{shelves}=Total floor space*proportion of shelves=3500m^{2} *0.25=875m^{2}](https://tex.z-dn.net/?f=6%2A10%5E%7B5%7D%2Ftex%5D%20books.%3C%2Fp%3E%3Cp%3EStep-by-step%20explanation%3A%3C%2Fp%3E%3Cp%3EHaving%20books%20on%20both%20sides%2C%20and%20each%20book%20being%2025%20centimeters%20%28there%20is%20100%20cm%20in%20a%20meter%2C%20so%2025%20cm%3D0.25%20m%29%20deep%2C%20shelves%20must%20be%20around%2050%20cm%20%28or%200.5%20m%29%20wide.%3C%2Fp%3E%3Cp%3EIf%20corridors%20must%20be%201%2C5%20m%20wide%2C%20every%20two%20linear%20meters%20%28perpendicular%20to%20corridors%20and%20shelves%29%20of%20floor%20space%20there%20is%201.5%20m%20of%20corridors%20and%200.5%20m%20of%20shelves%20and%20that%20sequence%20repeats%20itself%2C%20i.e.%20there%20is%2075%25%20%281.5%20of%20every%202%20meters%29%20of%20space%20occupied%20by%20corridors%20and%2025%25%20%280.5%20of%20every%202%20meters%29%20occupied%20by%20shelves%2C%20that%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DFloor%20space_%7Bshelves%7D%3DTotal%20floor%20space%2Aproportion%20of%20shelves%3D3500m%5E%7B2%7D%20%2A0.25%3D875m%5E%7B2%7D)
Knowing that every square meter of floor space occupied by shelves is in reality eight (because of being 8 shelves high) square meters of shelve space where to put books and that the average area of a book is

Having all the necessary data, we estimate how many books would this college library hold:

As it is an estimate, we round it up to the nearest hundred-thousand, i.e., approximately [tex]6*10^{5}/tex] books can be shelved on this library