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2 years ago

Suppose an isosceles triangle ABC has A= pi/6 and b=5=c. What is the length of a^2.

Mathematics

2 answers:

Oliga [24]2 years ago

3 0

Check the picture below.

mars1129 [50]2 years ago

3 0

Answer:

Option A. 5²(2-√3)

Step-by-step explanation:

In an isosceles triangle b = c = 5 and ∠A = π/6

By cosine rule in any triangle

a² = b² + c² - 2bc cosA

By putting the values of b, c and ∠A in the equation

a² = 5² + 5² - 2×5×5×cos(π/6) = 25 + 25 - (50√3/2) = 50 - 25√3

a² = 25(2-√3) = 5²(2-√3)

Therefore the answer is Option A. 5²(2 - √3)

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larisa86 [58]

Answer:

Point (1,8)

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$

Let us substitute coordinates of point P and Q as:

$x_1=-8$ ,

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$x_2=4$

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$m=3$

$n=1$

$[x=\frac{(3*4)+(1*-8)}{3+1},y=\frac{(3*12)+(1*-4)}{3+1}]$

$[x=\frac{12-8}{4},y=\frac{36-4}{4}]$

$[x=\frac{4}{4},y=\frac{32}{4}]$

$[x=1,y=8]$

Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.

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Svetach [21]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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