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GREYUIT [131]
3 years ago
7

Suppose an isosceles triangle ABC has A= pi/6 and b=5=c. What is the length of a^2.

Mathematics
2 answers:
Oliga [24]3 years ago
3 0
Check the picture below.

mars1129 [50]3 years ago
3 0

Answer:

Option A. 5²(2-√3)

Step-by-step explanation:

In an isosceles triangle b = c = 5 and ∠A = π/6

By cosine rule in any triangle

a² = b² + c² - 2bc cosA

By putting the values of b, c and ∠A in the equation

a² = 5² + 5² - 2×5×5×cos(π/6) = 25 + 25 - (50√3/2) = 50 - 25√3

a² = 25(2-√3) = 5²(2-√3)

Therefore the answer is Option A. 5²(2 - √3)

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A circle with radius of 1 cm sits inside a 11 cm x 12 cm rectangle. What is the area of the shaded region? Round your final answ
charle [14.2K]

Answer:

sry I just wanted the points I'm in middle school so I don't know this stuff either but can you give free brainlyest I'm soo close to my next rank I'd really appreciate it if you would

5 0
3 years ago
The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)
sveticcg [70]

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

  • The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
  • The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
  • If x and y coordinates are positive, then the angle lies in the 1st quadrant
  • If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
  • If x and y coordinates are negative, then the angle lies in the 3rd quadrant
  • If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point (\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = \frac{-\sqrt{2} }{2}

∴ cosФ = \frac{-\sqrt{2} }{2}

∵ y-coordinate = \frac{\sqrt{2} }{2}

∴ sinФ = \frac{\sqrt{2} }{2}

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = \frac{-\sqrt{2} }{2} ÷ \frac{\sqrt{2} }{2}

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

4 0
3 years ago
Read 2 more answers
Suppose that P(A)=0.5, P(B)= 0.4 and P(B/A) =0.6. Find each of the following.
Lady_Fox [76]

Part (a)

P(A) = 0.5

P(B) = 0.4

P(B/A) = 0.6

P(A and B) = P(A)*P(B/A)

P(A and B) = 0.5*0.6

P(A and B) = 0.3

<h3>Answer: 0.3</h3>

==========================================

Part (b)

We'll use the result from part (a)

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.5 + 0.4 - 0.3

P(A or B) = 0.6

<h3>Answer: 0.6</h3>

===========================================

Part (c)

A and B are not independent since P(B) does not equal P(B/A). The fact that event A happens changes the probability P(B). Recall that P(B/A) means "probability P(B) based on event A already happened". A and B are independent if P(B) = P(B/A).

Events A and B are not mutually exclusive since P(A or B) is not zero.

<h3>Answer: Neither</h3>
7 0
3 years ago
Jada uses 4cm tall bricks to build her tower.Her final tower is 80 bricks high.How many cm tall is it?
Alona [7]

Answer:

320

Step-by-step explanation:

4*80=320

3 0
3 years ago
Read 2 more answers
Please help me it is timed and i am running outta time
Westkost [7]

Answer:

In ∆RST and ∆XYZ

RS=YZ(S)

angle RST=angle XYZ(A)

ST=YZ(S)

hence ∆RST ≠~∆XYZ

7 0
3 years ago
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