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Nikitich [7]
3 years ago
7

Will vote brainliest.

Mathematics
1 answer:
Vlada [557]3 years ago
6 0

First you have to factor the equation because there are technically 2 x’s in an x^2. You will get x(x+6)=0 because x*x=x^2 and 6*x=6x. Now you can come up with possible values. If you make the first x, 0, you are multiplying everything by 0 and will get the product of 0. So, one of the and coordinates is x=0. You can also substitute -6 for the second x in the equation so that in the parentheses it would be x(-6+6)=0. You’re basically multiplying 0 by x which will guarantee you to get 0. So, the answer is (0,-6). If you have any questions feel free to comment.

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Step-by-step explanation:

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What is the product of the tens on 14 and 42
BartSMP [9]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Solve the system using elimination.
Molodets [167]

Answer:

(-1, 3)

Step-by-step explanation:

x - 5y = -16  [Equation 1]

-x + 3y = 10 [Equation 2]

<u>Adding both equations</u>

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5 0
2 years ago
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Find the HCF and LCM of 4x^2 - 36 ,2x^2 - 12x + 18 and 2x^2 + x - 21​
olga_2 [115]

Answer:

(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)

Step-by-step explanation:

Factor all the expressions,

1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)

2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)

3rd expression=2x^2 + x - 21​=(x - 3) (2 x + 7)

HCF=Commo factor=(x-3)

LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)

4 0
2 years ago
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