Answer:
Option B. is the answer.
Step-by-step explanation:
In the given picture we have to prove that quadrilateral HIJK is a kite.
1. For a kite quadrilateral HIJK will be a kite, if it's sides IJ = IH
From the graph length of I H = 4 - 1 = 3 units
Length of IJ = 0 - (-3) = 3 units
Therefore, IJ = IH = 3 units
2. Sides HK should be equal to JK
Length of HK =
by Pythagoras Theorem
= 
Similarly length of JK = ![\sqrt{(2)^{2}+[4-(-1)]^{2}}=\sqrt{4+5^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%282%29%5E%7B2%7D%2B%5B4-%28-1%29%5D%5E%7B2%7D%7D%3D%5Csqrt%7B4%2B5%5E%7B2%7D%20%7D)
= 
Therefore HK = JK = √29 units
3). IH ≠ JK and ij ≠ HK
All these conditions are fulfilled for HIJK to be a kite.
Option B. is the answer.