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2 years ago

15

What is a normal distribution with a mean of 0 and a standard deviation of 1 called?

1 answer:

Katen [24]2 years ago

3 0

It's called the <em>standard normal </em>(or <em>Gaussian</em>)<em> distribution</em>.

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What is 0.00277 scientific notation?

Harlamova29_29 [7]

2.77 × 10 ^ ( -3 ) is the answer

3 0

3 years ago

Read 2 more answers

What number is needed to complete the pattern below 66 73 13 21 52 _1020

Dimas [21]

<span>Answer 61 73-66= 7 21-13 = 8 ?? -52= 9 20-10 = 10 ??=61</span>

6 0

3 years ago

In STU, SU =18 and TU =13. Find m

erastova [34]

Answer:

m=22.2

Step-by-step explanation:

By using the Pythagorean’s theorem i.e

hypotenuse^2=opposite^2+adjacent^2

Where

Hypotenuse =unknown

Opposite =18

Adjacent =13

Hyp^2=18^2+13^2

Hyp^2=324+169

Hyp^2=493

Hyp=sqrt 493

Hyp=m=22.2

3 0

3 years ago

Is (1, 2) solution for this system of inequalities ?

diamong [38]

Answer:

MAYBE

Step-by-step explanation:

7 0

2 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

2 years ago