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pashok25 [27]
2 years ago
10

PLEASE HELP ITS MATH PLEASE

Mathematics
2 answers:
olganol [36]2 years ago
5 0

Answer:

y=[4]x + [12]

Step-by-step explanation:

Remember that parallel lines have identical slopes; and to make a line which passes through a point we will use point-slope form.

Familiarize yourself with point-slope form:

y-y1=m(x-x1)

If the line is parallel to y=4x+11 the slope must be 4.

y-y1=4(x-x1)

And we know the point it must pass through is (-2,4), so we can fill those values in too.

y-4=4(x+2)

Now all we have to do is solve for y:
y-4=4(x+2)\\y-4=4x+8\\y=4x+12

Marianna [84]2 years ago
3 0

Answer:

y = 4x + 12

Step-by-step explanation:

The solution is in the attached image

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The formula for the nth square number is S_n = n^2. Use the formula to find the 11th square number​.
Klio2033 [76]

Answer:

121.

Step-by-step explanation:

S_{11} = 11^{2} = 121. So, the 11th  square number is 121.

4 0
3 years ago
Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
Look at picture please :)
erma4kov [3.2K]

Answer:

To find the amount that it accelerated, you need to find the change in the mph.   First you would subtract 70 and 10 to find that number.  That tells you the total amount of change.  Then to figure out how much it would be per second you divided that number by the total number of seconds (12).

Step-by-step explanation:

5 0
3 years ago
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Dominik [7]

Answer:

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Step-by-step explanation:

3 v + 2 x

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3 ( - 1) + 2 ( -2)

-3 - 4

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%2B%20%20%7B5%7D%5E%7B2%7D%20" id="TexFormula1" title="4 + {5}^{2} " alt="4 + {5}^{2} "
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5 squared is 25. 25+4. Answer is 29
5 0
3 years ago
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