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algol13
3 years ago
11

PLEASE HELP WILL GIVE BRAINLIEST FOR ANSWER AND WORK

Mathematics
1 answer:
kolezko [41]3 years ago
7 0
P1 = 1(1 + 1) = 2
pk = k(k + 1) 
P_k+1 = (k + 1)(k + 1 + 1)
P_k+1 = (k + 1)(k + 2) I'm guessing at this: the notation is not the usual notation.
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How do you do this I have no idea
sveta [45]

Answer:

A

Step-by-step explanation:

Eliminate B C and D

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3 years ago
Your goal is to save $1200 to pay for next year's books and fees. How much must you save each month if you have 5 months to acco
Lady bird [3.3K]
All this is asking you is to find how much you need to save per month (limit of 5) in order to make your goal of $1200.

To solve this, simply divide 1200 by 5, which is the months, and you get $240, which is how much you have to save per month in 5 moths to reach your exact goal of $1200. If anything is confusing please ask :)
3 0
3 years ago
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What is 1 plus 894? I need help please
labwork [276]
It's is 895 because u add 4 with 1 so yeah it's 895
3 0
3 years ago
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Which of the following sets of possible side lengths forms a right triangle?
fenix001 [56]

Answer:

Which of the following sets of possible side lengths forms a right triangle?

<h3><em><u>11, 60, and 61</u></em><em><u>✓</u></em></h3>

6, 12, and 13

9, 40, and 45

12, 35, and 38

Step-by-step explanation:

\sqrt{ {11}^{2} +  {60}^{2}  }   \\ =  \sqrt{121 + 3600}  \\  =  \sqrt{3721}  \\  =  \sqrt{ {61}^{2} }  \\ =  61

<h3>11, 60 and 61 is the right answer.</h3>
8 0
3 years ago
8.Find the value of c that makes the expression be a perfect square trinomial p^2-30p+c
Darina [25.2K]
Hope this is the right one.

Problem 8
p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15

<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225

Problem Nine
\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10;
a = 1
b = 4
c = -15
\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} - 4*1*(-15) } }{2*1}
\text{x = }\dfrac{ -4 \pm \sqrt{\text{16} + \text{60} } }{2}

x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19) 

x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)

These two can be broken down more by finding the square root. I will leave them the way they are.  It's just a calculator question if you want it to go into decimal form.

Problem Ten

a = 1
b = 4
c = -32

The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12

Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y 
But that' s not what you were asked for.
The discriminate is >  0 so the roots are going to be real.
<em>Answer; The discriminate is > 0 so there will be 2 real different roots.</em>

4 0
3 years ago
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