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2 years ago

14

What is the next value 1I2L3F4

1 answer:

zmey [24]2 years ago

3 0

The given terms can be divided into two sections. First section is for the numbers and the second one for the letters.

1st section: 1, 2, 3, and 4
2nd section: I, L, F

I is the 9th letter in the alphabet, L is the 12th letter, and F is the 6th letter in the alphabet.

The pattern observed:
I to L: 12 - 9 = 3
L to F: 6 - 12 = -6

Next letter should be +9. This means that the letter should be 9 places higher than F. The letter should be O which is the 15th letter.

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sasho [114]

Here's what I got, hope it helps.

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3 years ago

Find the area below

Katyanochek1 [597]

Answer:

A = 693

Step-by-step explanation:

The shape presented is a parallelogram, and the formula for this is:

A = bh

The "b," is the base (21) and the "h," is the height (33), so plug this in:

A = (21)(33)

A = 693

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3 years ago

What is the percent error

RideAnS [48]

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3 years ago

Read 2 more answers

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago

Whats the sum and difference of 13-(-17)

ser-zykov [4K]

Sum= positive 30 because you add the opposite
The difference between the numbers is also 30

5 0

3 years ago