Let’s first find the angle y
Angle y = 180-(140+10)(angle sum property)
Angle y = 180-150
Angle y = 30 degrees
Angle x = 180- 110 ( linear pair )
Angle x = 70
Angle z = 180-(70+90)( angle sum property)
Angle z = 180-160
Angle z = 20
Answer:
See Explanation
Step-by-step explanation:
Now;
From;
P=Poe^kt
Where;
P = population at time=t
Po = population initially present
k = growth rate
t = time taken
a) The function is;
P= 112,000e^0.04t
b) In the year 2004, the population will be
P= 112,000e^0.04(6)
P= 142380
c) 200,000 =112,000 e^0.04t
200,000/112,000 = e^0.04t
1.786 = e^0.04t
ln 1.786 = ln e^0.04t
ln 1.786= 0.04t
t = ln 1.786/0.04
t = 14.5 years
let's recall that a year has 12 months, so 15 months is really 15/12 years.
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
