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Daniel [21]
3 years ago
15

How do you solve these

Mathematics
2 answers:
mestny [16]3 years ago
4 0
For number 1, you solve it like an equation.
My teacher always says this," Undo what has been done."
It means to do the opposite done to the variable.
3/8x>9
3/8 is being multiplied to the variable so if you do the opposite, you divide 3/8 to each side.
x>24

Number 2
21g>105
You divide each side by 21
g>5
MaRussiya [10]3 years ago
3 0
25)divide by 3/8 on both sides

 26) divide by 21 both sides
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Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
Please help I will reward Brainly
grigory [225]
V=(4/3)(pi)(r^3)
r=7
Hope this’ll help

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Step-by-step explanation:

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