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marusya05 [52]
3 years ago
14

Reversing coins there are n coins, each showing either heads or tails. we would like all the coins to show the same face. what i

s the minimum number of coins that must be reversed?
Mathematics
1 answer:
Katarina [22]3 years ago
8 0
If there are n coins, then the smallest (minimum) amount of coins we need to flip is 1. The reason why is because the best case scenario would be flipping all heads except the last coin which is tails. This scenario is rare if n is large, but still possible.
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The table below shows two equations:
ra1l [238]
The correct answer is option A A) Equation 1 and equation 2 have no solutions For the equation 1 l 3x-1 l +7=2 l 3x-1 l = 2-7 =-5 The absolute value should be positive So, there is no solution For the equation 2 l 2x+1 l +4 = 3 l 2x+1 l = 3 - 4= -1 The absolute value should be positive So, there is no solution
6 0
3 years ago
Read 2 more answers
On a spinner, there are 10 equal spots, numbered 1-10. What is the probability of spinning a 5 and then spinning a 5 again?
inessss [21]

Answer:

1 out of ten

Step-by-step explanation:

so if there are ten sides and all are numbered 1-10 then 5 is only one tenth.

8 0
3 years ago
The box and whisker plots below show two classes' semester grades. Write a paragraph comparing the two sets of
oksano4ka [1.4K]

The paragraph to show the comparision between two classes semester grades on the basis of the terms

  • extremes
  • quartiles
  • medians
  • ranges

is given below:

<h3>What is Box and Whisker plots?</h3>

A box and whisker plot is defined as a graphical method of displaying variation in a set of data.

From the first figure, write all the values where dark point is drawn

53, 62, 80, 86, 89  

  • The lower extreme is the smallest value, which is 53.

        The upper extreme is the highest value, which is 89.

  • The median will be the middle of data , which is 80

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

        The upper quartile is 86 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =89-53

       =36

From the second figure, write all the values where dark point is drawn

56, 62, 74, 89, 96

  • The lower extreme is the smallest value, which is 56.

        The upper extreme is the highest value, which is 96.

  • The median will be the middle of data , which is 74.

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

       The upper quartile is 89 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =96-62

       =34

From the above discussion,  

  • The First class have less upper extreme value than the second class.
  • The First class have less lower extreme value than the second class.
  • The First class have greater median than the second class.
  • The First class have less upper quartile than the second class.
  • The First and second class have equal lower quartile.
  • The First class have greater range than the second class.

The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.

learn more about box and whisper plot here:

brainly.com/question/11859288

#SPJ1

6 0
2 years ago
Find the number of positive integral solutions of ABC=45.
irina [24]
45=1×5×9 so 45×1×1=45. 5×9×1=45. 9×5×1=45. 45×1×1=45 .and ,then 1×5×9=45 sooo if ABC are treated as identical variables number of solutions can be those 5 steps about to find all the number of positive integral solutions ...
8 0
3 years ago
URGENT!!!!!!
patriot [66]

Answer:426.6

Step-by-step explanation:

.138 x =.088(x - 69.7) + .394(69.7)

.138 x -  .088x = 69.7(.394 - .088)

.05x = 21.3282

/

x = 426.564

This rounds to x = 426.6

<h2><u>Give me brainliest</u></h2>
6 0
2 years ago
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