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Anni [7]
3 years ago
7

Plz answer it will mean a lot

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Step-by-step explanation:

the answer is in the above image

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Consider the following figure where l1 and l2 are parallel and cut by transversals g1
vampirchik [111]

Answer:

helppppp

Step-by-step explanation:

3 0
3 years ago
this is 200 points my insta is niqdariot for the other 100 pleaseeeeeeeee help me asap its only 4 questions and I need all four
Kamila [148]

Answer:

19. parallel

20. corresponding

21. exterior

22. corresponding exterior angles

if not for the points i wouldve left u to suffer on ur own so yor welcome

8 0
3 years ago
Read 2 more answers
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B48x%7D%5E%7B4%7D%20" id="TexFormula1" title=" \sqrt[4]{48x}^{4} " alt=" \s
alex41 [277]

Answer:

48x

Step-by-step explanation:

(\sqrt[4]{48x} )^{4} = \sqrt[4]{(48x)^{4} } = 48x

7 0
3 years ago
In a classroom, 4/6of the students are wearing
Airida [17]
The answer is
4/6-3/6=1/6
6 0
2 years ago
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