The length of a rectangle is four times its width. if the perimeter of the rectangle is 80yd, find its length and width.
2 answers:
The length is 8. the width is 32.
32(2) = 64
8(2) = 16
64+16 = 80
So the length would be 8 and the width would be 32 since it's 4 times the length.
Hope this helped!
Lets assume Width=x and Length=Y
y=4x
P= 2(x+y)
80=2(x+4x)
80/2= 5x
40= 5x
x= 8
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