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Arisa [49]
2 years ago
7

Find an expression which represents the difference when (10x+6y) is subtracted from (6x-8y) in simplest terms

Mathematics
2 answers:
Anna007 [38]2 years ago
6 0

Answer:

x−14y

Step-by-step explanation:

(7x−8y)+(−6x−6y)

The "sum" is the result of addition

7x-8y-6x-6y

7x−8y−6x−6y

Remove parentheses

7x−8y−6x−6y

Identify like terms

7x−6x−8y−6y

Commutative property

7x−6x  

−14y

−8y−6y

​

Combine like terms

1x−14y

x−14y

Coefficient of 1 isn't needed

Tema [17]2 years ago
3 0

Answer:

4x+2y

Step-by-step explanation:

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miss Akunina [59]

Answer:

A: by emphasing the suffering of the Vietnamese people by reminding the country of its vow to protect Vietnam

Step-by-step explanation:

Hopefully this helps!

8 0
2 years ago
Which situations accurately describe a ratio of ? Select all that apply
Sav [38]
Where are the answer choices and the rest of the question?
5 0
3 years ago
Read 2 more answers
James runs laps around the park. The distance of a lap is d yards. On Monday, James runs 4 laps, Tuesday 3 laps, Thursday 5 laps
ra1l [238]

Answer:

d + 18

Step-by-step explanation:

6 0
3 years ago
A ball is thrown in the air from the top of a building. Its height, in meters above ground, as a function of time, in seconds, i
attashe74 [19]

The ball takes approximately a time of 2.041 seconds to reach its maximum height.

<h3>What time does the ball take to reach maximum height?</h3>

The height of the ball as a function of time is modelled by a <em>quadratic</em> equation, the required information can be found by transforming the expression into <em>vertex</em> form:

h = - 4.9 · t² + 20 · t + 12

h = - 4.9 · (t² - 4.082 · t - 2.449)

h + (- 4.9) · (6.615) = - 4.9 · (t² - 4.082 · t + 4.166)

h - 32.414 = - 4.9 · (t - 2.041)²

The ball takes approximately a time of 2.041 seconds to reach its maximum height.

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

5 0
1 year ago
-4+2(12)<br> ————<br> -3(-3)-(-1)
dsp73

Answer:

20/10 is 2

final answer is 2

8 0
3 years ago
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