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____ [38]
3 years ago
9

What is the slope of the line passing through the points (−3, 4) and (2, −1) ?

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0

Answer: Y2 - Y1

              ------------        =      -5/3

              x2 - x1

Don't Listen To Guy Below Me About English

Alex73 [517]3 years ago
4 0

d is is the defenit answer

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Janet has $120. If she saves$20 per week, in how many days will she have $500?
maxonik [38]
She will have $500 in 5 days because when she takes out the 20 every week she will have had $100 so to make $500 she will have to have made 5 $100
8 0
4 years ago
Can anybody solve this? If you will get it right I will mark you brainiest.
ikadub [295]

Answer:

The answer is one.

Step-by-step explanation:

I'm not exactly sure if I'm right , so sorry, if it's wrong

4 0
3 years ago
Read 2 more answers
You can do both problems if want
Agata [3.3K]
A= π r2 and v=3.14d

---Volume(v=3.14d):

3.14(15) equals 47.1

47.1 rounds to 47

nearest hundreth would be 0 that rounds to .1 or .10,which rounds to 47
v=47

---Area(π r2)

3.14(7.5)^2 is 3.14(56.25)
176.625

176.625 rounded to the nearest hundreth is 176.630.

Answer:

The area of a circle with the diameter of 15 is 176.630.
4 0
4 years ago
Simplify the following exponential expression. Show your work step by step and list the Properties of Exponents used to solve th
____ [38]

3x^0 (2x^3y^2)^4

--------------------------

(4x^7y^4) ^2


= 3 * 1  (2x^3y^2)^4

--------------------------      Zero Exponent Property  X^0 =1

(4x^7y^4) ^2


3   (2^4 *x^3*4 y^2*4)

--------------------------     power of a power property  x^a ^b = x^(a*b)

4^2 x^7*2 y^4*2

3   *16 *x^12 y^8

--------------------------     simplify

16 x^14 y^8

3    *x^12 y^8

--------------------------     simplify

x^14 y^8

3    *x^(12-14) y^(8-8)

--------------------------     Quotient of Power  X^a/ X^b = X^ (a-b)


3x^-2 y^0  simplify

3x^-2 *1      Zero Exponent Property  X^0 =1

3 / x^2   Negative exponent property  x^-a = 1/x^a

5 0
3 years ago
The equations -6x + 3y = 6 and x² + y = 10 intersect at the
eimsori [14]

The values of the letters in coordinates (a, b) and (c,d) are;

<u><em>a = -4</em></u>

<u><em>b = -6</em></u>

<u><em>c = 2</em></u>

<u><em>d = 6</em></u>

<u><em /></u>

We are given two equations;

-6x + 3y = 6  ---(eq 1)

x² + y = 10 ---(eq 2)

  • We are told that they intersect at coordinates; (a, b) and (c, d).

Let us make y the subject in eq 2 to get;

y = 10 - x²  --(eq 3)

  • Let us put 10 - x² into eq 1 to get;

-6x + 3(10 - x²) = 6

expanding further gives;

-6x + 30 - 3x² = 6

rearranging gives;

3x² + 6x - 24 = 0

Using online quadratic equation <em>solver</em>, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

y = 10 - (-4)²

y = 10 - 16

y = -6

Putting x = 2 into eq 3 gives;

y = 10 - (2)²

y = 10 - 4

y = 6

  • Thus, the coordinates are; (-4, -6) and (2, 6)

Comparing with (a, b) and (c,d), we have;

a = -4

b = -6

c = 2

d = 6

Read more at; brainly.com/question/15165519

5 0
3 years ago
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