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Ivan
3 years ago
9

Describe how the variability of the distribution changes as the sample size increases. As the sample size increases, the variabi

lity decreases. It cannot be determined. As the sample size increases, the variability stays the same. As the sample size increases, the variability increases.
Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

As the sample size increases, the variability decreases.

Step-by-step explanation:

Variability is the measure of actual entries from mean.  The less the deviations the less would be the variance.

For a sample  of size n, we have by central limit theorem the mean of sample follows a normal distribution for random samples of large size.

X bar will have std deviation as \frac{s}{\sqrt{n} }

where s is the square root of variance of sample

Thus we find the variability denoted by std deviation is inversely proportion of square root of sample size.

Hence as sample size increases, std error decreases.

As the sample size increases, the variability decreases.

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2 years ago
Solve using substitution <br> y= 7x + 6 <br> 4x - 3y =16
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Step-by-step explanation:

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4 0
2 years ago
Please help with this TWO ANSWERS required
lawyer [7]

Answer:

a) The equation of V and W

         V = k W

b) The value of  V = 666.6

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that V is inversely proportional to W

                       V∝ W

               ⇒      V = k W

              ⇒      40 = k (0.9)

              ⇒     k = \frac{40}{0.9} = 44.44

<u><em>Step(ii):-</em></u>

Given that W = 15  and k = 44.44

we have to find the value is 'V'

                       V = k W

            ⇒       V = 44.44 × 15

           ⇒        V = 666.6

           

3 0
2 years ago
Drag each tile to the correct box. In each of these scenarios, a credit card company has violated a federal or state law. Match
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7 0
3 years ago
a missile is launched from the ground. its height, h(x), can be represented by a quadratic function in terms of time, x, in seco
fomenos

Answer:

The height of the missile in the air  after 11 seconds is 330 feet.

Step-by-step explanation:

The standard form for the quadratic function f(x)= ax^2 + bx + c, which is the function of the parabola model.

We are given two points.

(1, 130) and (2, 240)

Here the first coordinate represents the x (time) and the second coordinate represents h(x), which is height.

Now plug these two coordinates and find the two equations.

(1, 130), the equation is

130 = a.(1)^2 + b(1) + c, where "c" is the initial height. Which is equal to zero.

Therefore, we get

130 = a + b + 0

a + b = 130 -------(1)

Now let's form the second equation using the coordinate (2, 240)

240 = a(2)^2 + b(2) + 0

240 = 4a + 2b -------------(2)

Now let's solve the equations (1) and (2) and find the value of "a" and "b"

a + b = 130 can be written as a = 130 - b

Here we can use the substitution method.

Now plug in a = 130 - b in the second equation, we get

240 = 4(130 - b) + 2b

240 = 520 - 4b + 2b

240 = 520 - 2b

2b = 520 - 240

2b = 280

Dividing both sides by 2, we get

b = 140

Now plug in b = 140 in a = 130 -b and find the value of a

a = 130 - 140

a = -10

Now we got a = -10 and b = 140.

We plug in a = -10 and b = 140 in the general form, we gety

h(x) = -10x^2 + 140x + c

Where c is the initial height, which is equal to 0.

h(x) = -10x^2 + 140x

Now plug in x = 11 seconds and find the height.

h(11) = -10(11)^2 + 140 (11)

= -10 (121) + 1540

= - 1210 + 1540

h(11) = 330 feet,

Therefore, the height of the missile in the air  after 11 seconds is 330 feet.

6 0
3 years ago
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