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Sliva [168]
3 years ago
9

Please help, I'm giving Brainliest to the right answer!!

Mathematics
2 answers:
Neko [114]3 years ago
7 0
The correct answer is  D

laila [671]3 years ago
6 0

Answer:

Option  D is correct.

75m = 50(12)+125(m-12)

Step-by-step explanation:

Here, m represents the months.

We have to find the equation for which Plans A and B cost the same.

In Plan A:

No initial fees.

$75 per month.

For 1 month = $ 75

then;

for m month =$ 75 m

⇒Total cost for plan A =  75m

In Plan B:

$50 per month for first 12 month.

For 1 month = $ 50

for 12 months = 50(12)

Similarly for:

$125 per month for each additional month after that.

For additional month (m-12) = 125(m-12)

then

Total cost for plan B = 50(12)+125(m-12)

Since, Plans A and B cost the same.

⇒75m = 50(12)+125(m-12)

Therefore, an equation gives the correct value of m, the number of months for which Plans A and B cost the same is, 75m = 50(12)+125(m-12)

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astra-53 [7]

Answer:

Create a black dot that is filled in, then an arrow going towards the right.

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Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

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c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

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3 years ago
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