Answer:
x=0 y=-11 (0,-11)
Step-by-step explanation:
1. take what y equals (3x-11) and plug it in for y in the second equation
Should look like this: O= 6x-2(3x-11)-22
2. Then distribute O=6x-6x+22-22
3. Then combine like terms O= 0 the 22's cancel out as well as the x's
x= 0
4. plug 0 in for x in the first equation y=3(0)-11
5. y= -11
6. x=0 y=-11 (0,-11)
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
i believe she spent $4.482 on clementines
(-1,8) is the correct answer I’m pretty sure