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rusak2 [61]
3 years ago
8

Use the given conditions to write an equation for the line in​ point-slope form and general form. Passing through (7 , 9 )and pa

rallel to the line whose equation is 7 x - 5 y -9= 0

Mathematics
1 answer:
levacccp [35]3 years ago
3 0
When the given line is in standard form or general form (as here), the desired line can be found by replacing the constant by zero, and then translating the line to the given point.

The starting point for your solution can be
  7(x-7) - 5(y-9) = 0

In general form, this is
  7x - 5y - 4 = 0

In point-slope form, this is
  y - 9 = (7/5)(x - 7)

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Evaluate the expression: -(8 - 12) + 6° + (-4)2.
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-4 + 6°

Step-by-step explanation:

- (8 - 12) + 6° + (- 4)2 = - ( - 4) + 6° - 8 = 4 + 6° - 8 = - 4 + 6°

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Given parallelogram EFGH with diagonals that intersect at point J, which statement is true? Diagonal segment EG is perpendicular
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7 0
4 years ago
Evaulate the function at the indicated values h(t)=t+(3/t)i find h(x-1)
alex41 [277]

<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>

Note that the domain of h is <span>[0,∞]</span>.

By differentiating,

<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>

by factoring out <span>34</span>,

<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>

by finding the common denominator,

<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>

<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>

Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.

Hence, the critical numbers are <span>t=0,1</span>.

I hope that this was helpful.

6 0
3 years ago
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