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Andrews [41]
3 years ago
9

An airline claims that the no-show rate for passengers booked on its flights is less than 6%. of 380 randomly selected reservati

ons, 18 were no-shows. assuming that this data is used to test the airline's claim, find the p-value for the test. 0.3508 0.1499 0.1230 0.0746
Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0
The p-value of the test is the calculated probability. Hence, the probability must be 18/380. In simplified terms, this is equal to 0.0474 or 4.74%. This is the p-value of the test. The null hypothesis is p < 6%. According to the test, the p-value is 4.74%. Therefore, the null hypothesis is accepted. 

The answer is not among the choices. The answer must be 0.0474 or 4.74%.
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Apr 17, 1:48:02 AM
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Answer:

y = 9.54

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Step-by-step explanation:

Given that

x - 2y = -19 .......................(1)

3x + 5y = 48 ...............(2)

Based on the above information

Multiply by 3 in equation 1

So,

3x - 6y = -57

3x + 5y = 48

-     -        -

-11y = -105

y = 9.54

So, the x would be

x - 2(9.54) = -19

x - 19.08 = -19

x = -19 + 19.08

x = 0.08

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Answer:

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