The answer would ve B. -204.8 the sum
The answer is: z² .
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Given: <span>(x÷(y÷z))÷((x÷y)÷z) ; without any specified values for the variables;
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we shall simplify.
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We have:
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</span>(x÷(y÷z)) / ((x÷y)÷z) .
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Start with the first term; or, "numerator": (x÷(y÷z)) ;
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x ÷ (y / z) = (x / 1) * (z / y) = (x * z) / (1 *y) = [(xz) / y ]
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Then, take the second term; or "denominator":
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((x ÷ y) ÷z ) = (x / y) / z = (x / y) * (1 / z) = (x *1) / (y *z) = [x / (zy)]
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So (x÷(y÷z)) / ((x÷y)÷z) = (x÷(y÷z)) ÷ ((x÷y)÷z) =
[(xz) / y ] ÷ [x / (zy)] = [(xz) / y ] / [x / (zy)] =
[(xz) / y ] * [(zy) / x] ;
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The 2 (two) z's "cancel out" to "1" ; and
The 2 (two) y's = "cancel out" to "1" ;
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And we are left with: z * z = z² . The answer is: z² .
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=(14+3i) - (-12-7i) + (6+2i)
=14 + 3i +12 + 7i + 6 + 2i
=32 + 12i
Answer: odd and positive
How to find number of degrees: Count the number of turns and add one. In this case you have 4 curves, so 4+1= 5.
How to find leading coefficient: look at the RIGHT side of the graph, the arrow is going towards positive infinity, thus making the leading coefficient positive.
113 is one number. 131 is another
137, 173
I think that's all of them.
You can check if you google 'list of primes'.
Hold on i'm not sure about 113 and 131 Is number 1 a prime number? I dont think it is , So that leaves us with only 137 and 173.
