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Maksim231197 [3]
3 years ago
6

What is the domain of the following quadratic equation? f(x)=2x^2+5x-7

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
Domain is th enumbers you can use and not cause conflict (like dividing by 0 or something)

actually, the domain is all real numbers
there is no real value of x that will make us divide by 0 or take the square root of a negative number

domain is all real numbers
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Priya says the area of the large unmarked square is 26 square units because: 9+17=26. Do you agree with Priya?
Rudik [331]
Nope because she only used two of the net faces
5 0
3 years ago
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Find the midpoint of a segment whose endpoints are (9, –7) and (–3, 5).
suter [353]
For this question, you would have to use the midpoint formula. 
(X1 +X2 / 2 , Y1 + Y2 / 2)

In other words, 
(9 + -3 / 2 , -7 +5 / 2)
(6 / 2 , -2 / 2)
(3 , -1)

Your midpoint is (3, -1)
7 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
4 years ago
Point J is on line segment IK. Given JK = 2x – 1, IK = 3x + 2,
Serhud [2]

Answer:

JK=7

Step-by-step explanation:

From the line segment, since J is on it ,it means the line segment is

represented as I J K

from this illustration, we can say that the longest part of the line segment is from I to K

this means that, IJ +JK =IK

making JK the subject,

JK= IK - IJ

but from the question, JK=2x-1 , IK=3x+2 and IJ=3x-5

substituting them in the expression,

2x-1 =3x+2 -(3x-5)

solving for x

2x-1 =3x+2-3x+5

2x-1 =0+7

2x-1 =7

2x=1+7

2x=8

dividing through by 2

2x/2 =8/2

x=4

but the question says we should find the numerical value for JK

but from the line segment,

JK=2x-1

but now we know the value of x to be 2

so substituting it in the formula

JK= 2(4)-1

JK=8-1

JK=7

therefore, the numerical value for JK is 7

4 0
3 years ago
Need help ()()()()()((;(;
Gwar [14]

Answer:

20%

Step-by-step explanation:

4/20 = x/100

100*4 =400

400/20 = 20

so

4/20 = 20/100

8 0
3 years ago
Read 2 more answers
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