Multiply both sides of the second equation by 100 to get rid of the decimals:
0.05<em>n</em> + 0.10<em>d</em> = 1.50
==> 5<em>n</em> + 10<em>d</em> = 150
Multiply both sides of the first equation by -5:
<em>n</em> + <em>d</em> = 21
==> -5<em>n</em> - 5<em>d</em> = -105
Add the two equations together:
(5<em>n</em> + 10<em>d</em>) + (-5<em>n</em> - 5<em>d</em>) = 150 + (-105)
Notice that the terms containing <em>n</em> get eliminated and we can solve for <em>d</em> :
(5<em>n</em> - 5<em>n</em>) + (10<em>d</em> - 5<em>d</em>) = 150 - 105
5<em>d</em> = 45
<em>d</em> = 45/5 = 9
Plug this into either original equation to solve for <em>n</em>. Doing this with the first equation is easiest:
<em>n</em> + 9 = 21
<em>n</em> = 21 - 9 = 12
So Donna used 12 nickels and 9 dimes.
A. all real numbers for both
Explanation:
Domain is the x-values. Since the graph goes forever horizontally, any x-value is on the graph.
Range is the same but with y-values. If the graph went on further than what the picture shows, then it also would show that every y value is on the graph
hope this helps
Answer:number one=0.4667 and two is 0.44444444444
Step-by-step explanation:
The quotient is x^2
The remainder is 2
Step-by-step explanation:
We need to divide: 
The division is shown in figure attached.
The quotient is x^2
The remainder is 2
Keywords: Division of polynomials
Learn more about Division of polynomials at:
#learnwithBrainly
Answer:
a) 3/5 < 4/5
b) In general if two fractions have the same denominator, then whichever fraction has the numerator closer to its denominator will be the largest fraction.
c) 
<em>or</em> 
Step-by-step explanation:
a) 3/5 < 4/5
Flip the sign and the placement of the fraction so 3/5 is less then 4/5.
b) In general if two fractions have the same denominator, then whichever fraction has the numerator closer to its denominator will be the largest fraction.
c) We need to change the denominators to a common denominator to compare the size of the two fractions:
× 
= 
× 
= 
The common denominators of the two fractions is 30. Comparing the two fractions:
<em>or</em> 
so we get: <em>or</em>
