The answer would be C. 5m
This is because to find d, you would need to divide W (125 J) by F (25 N).
Hope this helps!
Answer:
The terms of biosafety in a laboratory require that the person must not have the eyes and skin exposed.
Explanation:
A corrosive substance is a substance that can damage a surface when they come into contact.
These substances represent a danger in people since they can burn the eyes, the skin, and the inside of the body since the inhalation of gases can burn the respiratory tract.
These chemical burns can be avoided by properly following the biosafety protocol that a laboratory requires the use of masks, goggles, gloves, and an apron or lab coat.
When you grow your brain grows its very complicated you cant just GET smart you have to learn easy stuff like 2+2 to 83x17 more you grow more your brain grows more stuff you learn but to get smarter read more do math more JUST DO EVERYTHING MORE to grow your brain and fill in your brain
Every living thing would die
Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
