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Softa [21]
3 years ago
12

the speed of light in a piece of plastic is 2.00x10^8 meters per second what is the absolute index of refraction of this plastic

Physics
1 answer:
marta [7]3 years ago
6 0
The speed of light in a material with refractive index n is modified according to the following law:
v= \frac{c}{n}
where c is the speed of light in vacuum (c=3\cdot 10^8 m/s), while v is the speed of light in the medium (v=2 \cdot 10^8 m/s). Re-arranging, we can find the refractive index of this plastic:
n= \frac{c}{v}= \frac{3 \cdot 10^8 m/s}{2 \cdot 10^8 m/s}=1.5
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Answer:

I believe 0 N

Explanation:

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The following situations apply: A, B, D.

Explanation:

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3 years ago
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Answer:

u = 88.54 m/s

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