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Daniel [21]
3 years ago
12

Kitty is pushing her shopping trolley along the ground. She applies a constant force to move the trolley 4 m horizontally. If sh

e does 32 J of work, calculate how much force she is applying.
Physics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

the constant force applied by Kitty is 8 N.

Explanation:

Given;

work done by Kitty, W = 32 J

distance moved by Kitty's trolley, d = 4 m

Let the constant force applied by Kitty = F

The work done by Kitty is calculated as follows;

W = F x d

F = W / d

F = 32 / 4

F = 8 N.

Therefore, the constant force applied by Kitty is 8 N.

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Answer:

As waves get closer to a beach they decrease in height.

Explanation:

As a wave crest approaches the shoreline, it is usual that one end of the line is closer to the shoreline than the other. The implication of this is that the energy in a wave is also spread over quite a larger area,this in turn reduces the height of the waves. In other words, refraction often makes waves smaller.

Waves are caused by wind. Wave height in the open ocean is determined by three factors. The greater the wind speed the larger the waves. The greater the duration of the wind (or storm) the larger the waves. The greater the fetch (area over which the wind is blowing - size of storm) the larger the waves.

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3 years ago
A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to res
Natali5045456 [20]

Answer:

(a) F = 239.575 N (b) t = 0.00649s or 6.49 ms

Explanation:

(a) By law of energy conservation, the bullet kinetic energy will be transferred to work done on stopping it from moving.

Formula for Kinetic Energy E_k = \frac{mv^2}{2} where m is bullet mass, v is the velocity

Formula for work W = FS where F is the average force and S is the distance travelled.

E_k = W

\frac{mv^2}{2} = FS

F = \frac{mv^2}{2S}

Substitute m = 4.2 g = 0.0042 kg, v = 370 m/s and S = 1.2 (m)

F = \frac{0.0042*370^2}{2*1.2} = 239.575 N

(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

a = \frac{F}{m} = \frac{239.575}{0.0042} = 57041.67 (m/s^2)

We also have v(t) = v_0 + at

At the time the bullet is coming to rest, v(t) = 0, a = -57041.67 m/s^2

Therefore, 0 = 370 - 57041.67t

t = \frac{370}{57041.67} = 0.00649 s = 6.49 ms

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Answer:

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