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mezya [45]
3 years ago
5

Evaluate the function rule to find the range of each function for the domain.

Mathematics
1 answer:
aev [14]3 years ago
5 0
F(x) = x^2 - 6x + 4               {-3, 0, 5}   (x, y) x is the domain, y is the range.

plug in the domain numbers into the equation to find the range.

y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31                        (-3, 31)

y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4                       (0, 4)

y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1                       (5, -1)

c. {-1, 4, 31}

hope this helped, God bless!
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Answer:

The mean and standard deviation of Y is $6.56 and $2.77 respectively.

Step-by-step explanation:

Consider the provided information.

Let Y represent their profit on a randomly selected pizza with this promotion.

The company is going to run a promotion where customers get $2 off any size pizza.

Therefore, Y=\text{Profit}-\$2

Y=X-\$2

So the mean will be reduced by 2.

\mu_Y=\mu_X-\$2

\mu_Y =\$ 8.56 - \$2

\mu_Y =\$6.56

If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.

Therefore \sigma_Y=\sigma_X=2.77

Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.

3 0
3 years ago
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su
Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=2-x^2

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = 2-p^2

Area = l*w = 2(2p-p^3)

Use derivative test

I derivative = 2(2-3p^2)

II derivative = -12p

Equate I derivative to 0 and consider positive value only since we want maximum

p = \sqrt{\frac{2}{3} }

Thus width= \sqrt{\frac{2}{3} }

Length =2\sqrt{\frac{2}{3} }

Width = 2-2/3 = 4/3

3 0
3 years ago
Functions<br> Find the value<br> f(x)=2x-6<br> x=(7)-9<br> Does X = -2?
hichkok12 [17]
Yes x=-2. You are doing great! Keep it up! Mark as brainliest! :)
7 0
3 years ago
? Help
svlad2 [7]

Answer:

9

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the average rate of change of a function that contains the points (-2,3) and (2,5). -2, -1/2, 1/2, 2
UkoKoshka [18]

Answer:

The answer is "\frac{1}{2}".

Step-by-step explanation:

Given points:

(-2,3)\\\\(2,5)\\\\

average rate=?

x_1=-2\\\\y_1=3\\\\x_2=2\\\\y_2=5

average\ rate=\frac{y_2-y_1}{x_2-x_1}

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5 0
2 years ago
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