Cos (a-b) - cos (a+b) = 2 sin a sin b

1 answer:

4 0

cos(a - b) - cos(a + b) = 2sin(a)sin(b)
[cos(a)cos(b) + sin(a)sin(b)] - [cos(a)cos(b) - sin(a)sin(b)] = 2sin(a)sin(b)
[cos(a)cos(b) - cos(a)cos(b)] + [sin(a)sin(b) + sin(a)sin(b)] = 2sin(a)sin(b)
2sin(a)sin(b) = 2sin(a)sin(b)

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The length of AB will be 10 units. Option B is corect. The formula for the distance between the two points is applied in a given problem.

<h3>What is the distance between the two points?</h3>

The length of the line segment connecting two places is the distance between them.

The distance between two places is always positive, and equal-length segments are referred to as congruent segments.

The given coordinate in the problem is;

(x₁,y₁)=(-2,-4)

(x₂, y₂)= (-8, 4)

The distance between the two points is found as;

$\rm d= \sqrt{(-8-(-2))^2+(4-(-4))^2}\\\\ d=10 \ units$