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Brums [2.3K]
3 years ago
14

A stereo system is being installed in a room with a rectangular floor measuring 11 11 feet by 10 10 feet and a a 9 9​-foot ceili

ng. The stereo amplifier is on the floor in one corner of the room. A speaker is at the ceiling in the opposite corner of the room. You must run a wire from the amplifier to the​ speaker, and the wire must run along the floor or walls​ (not through the​ air). What is the shortest length of wire you can use for the​ connection? (Hint: Turn the problem into an equivalent simpler problem by imagining cutting the room along its vertical corners and unfolding it so that it is flat. You will be able to apply the Pythagorean​ theorem.)
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0

Answer:

idkhhfrdssefghujhgjjuuu

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Initially, there were equal amount of roses and tulips at a store. Each bouquet was made with 3 roses and 4 tulips. After the bo
adelina 88 [10]

Answer:There were 10 bouquets of roses made and 4.5 bouquets of tulips made

Step-by-step explanation:

8 0
3 years ago
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

7 0
3 years ago
What is 4-2x+8+5x simplified
sveta [45]

Answer: it is 3 • (x + 4)

Step-by-step explanation: We move all terms to the left:

4-2x+8-(+5x)=0

We add all the numbers together, and all the variables

-2x-(+5x)+12=0

We get rid of parentheses

-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7We move all terms to the left:

4-2x+8-(+5x)=0

We add all the numbers together, and all the variables

-2x-(+5x)+12=0

We get rid of parentheses

-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7

6 0
3 years ago
Read 2 more answers
What is the area of this figure?
s2008m [1.1K]

Step-by-step explanation:

it clearly consists of 2 rectangles and 1 triangle (as you tried correctly to point out by drawing the separating lines).

we only need to calculate all 3 areas and add them up for the total.

the area of a rectangle is

length × width

so, in our 2 cases we have

6 × 2 = 12 km²

5 × (3 + 2 + 3) = 5×8 = 40 km²

the area of a triangle is

baseline × height / 2

in case of a right-angled triangle the 2 sides enclosing the 90° angle can be used as baseline and height.

so, in our case

6 × (5 + 2 + (3 + 2 + 3 - 2)) / 2 = 6×(7 + 6)/2 = 3×13 = 39 km²

in total, the whole area is

12 + 40 + 39 = 91 km²

4 0
2 years ago
How to find area of parallelogram with coordinates of verticles?
ExtremeBDS [4]
You find a parallelogram area by this formula:
A=b\cdot h
Where b is its base and h, its height.
You get b's value applying distance between two points formula.
If A and B points form the base:
A(x_1,y_1)\;\;\;\;B(x_2,y_2) \\  \\ 
d_{AB}= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} =b

And h is the perpendicular distance between both bases.
You can visit next link to know further about it:
https://www.ck12.org/geometry/Distance-Between-Parallel-Lines/lesson/Distance-Between-Parallel-Lines
-GEOM/

And in attached picture you can find an example in progress you may want to finish.

5 0
3 years ago
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