4 years ago

Square root of 216k^4

Mathematics

1 answer:

Kitty [74]4 years ago

7 0

Remember
$\sqrt{ab}=(\sqrt{a})(\sqrt{b})$

so
$\sqrt{216k^4}=(\sqrt{216})(\sqrt{k^4})=(6\sqrt{6})(k^2)=6k^2\sqrt{6}$

You might be interested in

PLEASE HELP ME WITH EMPIRICAL RULE!! ASAP!

Nat2105 [25]

Answer:

hahahahahahahahahahhahahahahhahahahahhahagagagaggagagagahhahahahahha

8 0

3 years ago

after 1 year on the job M got a raise from $10.50 to $11.13 per our. What was the percent increase of her hourly wage

N76 [4]

The answer is 6% increase

6 0

3 years ago

I don't know how to explain it

Lemur [1.5K]

Answer:

Sam's thinking was incorrect.

On number first we have to move 10 units from 0 in positive direction after that negative sign means move in left direction.

But we have 2 negative signs so we need to move 6 units more on positive or right direct as shown below.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Ollie won 2 games for every 5 games that Noelle won. If Noelle won 15 more

Dmitrij [34]

Answer:

Step-by-step explanation:

2:5, 4:10, 6:15

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=

KiRa [710]

$e ^{2x} = ln5$

Solve for the real domain

$e ^{2x} = ln(5)$

if $f(x) =g(x),$ then $ln(f(x))= ln(g(x))$

$ln(e ^{2x} ) = ln(ln(5))$

Solve : <span> $ln(e ^{2x} ) = ln(ln(5))$
</span>
use the logarithmic definition :

$ln(e^{f(x)} ) = f(x)$

$ln(e^{2x} ) = 2x$

$2x=ln(ln(5))$

Divide both sides by 2 :

$\frac{2x}{2} = \frac{ln(ln(5))}{2}$

$x= \frac{ln(ln(5))}{2}$

hope this helps!

8 0

3 years ago