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4 years ago

You roll a fair six sided die what is payroll greater than six

Mathematics

1 answer:

Furkat [3]4 years ago

5 0

Answer:

Step-by-step explanation:

A fair sided die has 1,2,3,4,5,6

There is no number greater than 6

P(number greater than 6) = numbers greater than 6/ total

=0/6

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1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago

An artist mixes white and green paint at a ratio of 7:2 . How many ounces of white should the artist add to 6 ounces of green pa

Reil [10]

$\frac{w}{g} = \frac{7}{2} = \frac{x}{6} \\ x = \frac{7 \times 6}{2} = 21$

7 0

3 years ago

The cone shown has a radius of 5 inches and a slant height of 8 inches rounded into the nearest whole number what is the total s

svlad2 [7]

The formula to find the surface area is 3.14(radius)(slant) + 3.14 (radius squared). So the equation would be (3.14)(5)(8)+(3.14)(5^2) for your answer you should get 204 square inches. Hope that helped!

5 0

3 years ago

valentinak56 [21]

9514 1404 393

Answer:

30x +25y = 148

Step-by-step explanation:

We can use substitution to find the point of intersection of ...

3x +14 = 2y
x + y = 6

Using the second equation, we can write an expression for y:

y = 6 -x

Substituting that into the first equation gives ...

3x +14 = 2(6 -x)

3x +14 = 12 -2x . . . . . eliminate parentheses

5x = -2 . . . . . . . . . . . add 2x-14

x = -0.4 . . . . . . . . . divide by 5

y = 6 -(-0.4) = 6.4

Now, we want an equation for a line through the point (-0.4, 6.4) that is perpendicular to 5x = 6y+1

The perpendicular line will have the coefficients swapped with one of them negated. The constant will accommodate the given point.

6x = -5y + c

6(-0.4) +5(6.4) = c = 29.6

The perpendicular line can be written ...

6x = -5y +29.6

In standard form, the equation is ...

30x +25y = 148

4 0

3 years ago

F(x)=-1/4(x-6) to the power of 2

katovenus [111]

what are you asking for simplify solve or what

8 0

4 years ago